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The Fourier transform is also applied for solving the differential equations that relate the input and output of a system. The Laplace transform can be used to analyse unstable systems. Fourier transform cannot be used to analyse unstable systems. The Laplace transform is widely used for solving differential equations since the Laplace transform exists even for the signals for which the Fourier transform does not exist.
The Fourier transform is rarely used for solving the differential equations since the Fourier transform does not exists for many signals. Now consider a periodic continuous time signal x nT. Take a product of the above two signals as shown below.
Multiplying a continuous time signal with an impulse signal is known as the impulse sampling of a continuous time signal. Taking Laplace transform of the above signal and using the identity Thus, Which can be written as: Compare this equation with that of z-transform Thus we finally get the relation: Derived from the Impulse Invariant method Another representation: Derived from Bilinear Transform method Mapping the s-plane into the z-plane Mapping of poles located at the imaginary axis of the s-plane onto the unit circle of the z-plane.
This is an important condition for accurate transformation. Mapping of the stable poles on the left-hand side of the imaginary s-plane axis into the unit circle on the z-plane. Another important condition. Poles on the right-hand side of the imaginary axis of the s-plane lie outside the unit circle of the z-plane when mapped. Thus we can say that the z-transform of a signal evaluated on a unit circle is equal to the fourier transform of that signal.